| Section | Exercises |
| 1.1 | 9, 12, 14, 25, 26 |
| 1.2 | 25, 30, 32 |
| 1.3 | 3, 5, 9, 13, 14, 18, 19 |
| 1.4 | 8, 15, 18, 21, 23 |
| 1.5 | 13, 19, 27 |
| 1.6 | 7, 9, 16 |
| 2.1A | 5, 9, 12 |
| 2.2C | 9, 13, 19, 24, 28 |
| 2.2D | 2, 4, 10, 11 (see errors) |
| 2.3 | 6, 10, 17, 33, 39 |
| 2.4 | 8, 9, 19, 21, 23 |
| 2.5 | 5, 6, 8, 9, 11 (use #12), 17, 18 |
| 3.1 | 1, 4, 5, 8, 9, 10, 13, 19, 23 |
| 3.2 | 7-11, 13, 16, 17, 20, 26, 27 |
| 3.3 | 6-8, 11, 15-17, 20, 24, 27 |
| 3.4 | 5, 6, 9, 13, 17, 19, 20, 21 |
| 3.5B | 3, 8, 10, 13, 17, 27, 35, 40, 41 |
| 3.5C | 1, 3, 4, 11, extra problems 1-3 |
| 3.6A | 3, 5, 6, 8, 15, 17 |
| 3.6C | 2, 3, 8, 11, 13, 16, 19, 21 |
| 3.7A | 2-5, 7, 8, 11, 13 |
| 3.7B | 3-5, 7, 8, 11, 12, 17, extra problem 4 |
| 3.7C | 1-3, 5 (see errors) |
| 14.6 | 3, 7 |
| 14.7 | 2, 5, 7, 8, extra problem 5 |
| 14.8 | 3, 5, 9, 22, 23, 31, 32 |
| 14.9 | 2, 5, 7, 13, 15 16 |
| 14.10B | 3, 5, 9, 15, 16, 23, 30, extra problem 6 |
L[p] = (x2+2)p″ + (x-1)p′ - 4p .
Find the matrix for L. Find bases of polynomials for the image and null space of L.
| 1 | -2 | 3 | 3 |
| 2 | -5 | 7 | 3 |
| -1 | 3 | -4 | 3 |
∂u/∂ t = ∂2u/∂r2 + r-1 ∂u/∂r + r-1∂2u/∂θ2.
Given that u=u(r,t) (no angular dependence), u(a,t) = 0, and assuming that u is continuous at r = 0, separate variables.Updated 8/24/05 (fjn).