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 \centerline{\large Math.\ 401, Sec.\
500\hfill    Spring, 2005}
 \bigskip
\centerline{\bfseries\large Homework 14, due May 6, noon}
\medskip
\centerline{This is an optional assignment for extra credit.}
\bigskip

Turn in at most two of these problems.  Do not do both problems 
marked ``$*$''\negthinspace.

% ``On my honor, as an Aggie, I have neither given nor received 
% unauthorized aid on this academic work.''
 
\begin{enumerate}
 

  \item $*$ Consider the Green function for the Laplace problem 
in the upper half plane,
 $$G(x-z,y) = \frac1{\pi}\, {y\over (x-z)^2 +y^2}\,.$$

\begin{enumerate}
 \item Verify that $G$ satisfies Laplace's equation as a
function of $x$ and $y$.

 \item  Show that $\displaystyle \int_{-\infty}^\infty G(x-z, 
y)\, dz =1$
 for each fixed $x$ and $y$.

 \item Let $z=1$ and sketch $G(x-1, y)$ as a function of $x$
for three representative values of $y$.

 \item  Justify the claim that
 $$\lim_{y\to 0^+} G(x-z, y) = \delta(x-z).$$
 This means that for any well-behaved function $f$ (say $f$
continuous and bounded),
 $$\lim_{y\to 0^+} \int_{-\infty}^\infty G(x-z, y)\, f(z)\,dz= 
f(x).$$
{\sl Hints:\/}
 Write the integral as 
 $\int_{-\infty}^{x-\delta} + \int_{x-\delta}^{x+\delta} 
+\int_{x+\delta}^\infty$, 
 where $\delta$ is an arbitrarily small positive number. 
 Show that the two outside integrals approach zero in the limit,
using the assumption that $f$ is bounded.
 In the middle integral, write 
 $f(z) = f(x) + [f(z)-f(x)]$
 and show that the integral involving the bracketed term can be 
assumed arbitrarily small,
 using the assumption that $f$ is continuous.


 \item Argue (a bit loosely, perhaps) from (a) and (d) that
 $G$ is the correct Green function for the problem --- without
appeal to Fourier transforms or any other external information.
 (That is, show that
 $$u(x,y) \equiv \int_{-\infty}^\infty G(x-z,y)\, f(z)\,dz$$
 is the bounded solution of Laplace's equation in the upper half plane with
the boundary data $u(x,0)=f(x)$.)
\end{enumerate}


\item  Using the $\delta$-function method, construct Green 
functions to solve these problems:

\begin{enumerate}
\item \quad $\displaystyle {d^2y\over dx^2} +\omega^2 y = f(x), 
\qquad
y'(0)=0, \quad
y'(2)=0.$ \newline
(Assume $\omega>0$.  For what values of $\omega$ does no solution 
exist?)

\item \quad $\displaystyle{d y\over dt} -y = f(t), \qquad 
y(0)=0.$ \newline
{\sl Warning:\/} In this case, $G$ is {\sl not\/} continuous at 
the location of the delta function.

\end{enumerate}





\item $*$ 
\begin{enumerate}
 \item Solve the wave equation in $\mathbf R^2$ by Fourier 
 transforms, and rearrange the result into the form
 $$u(x,t) = \int_{-\infty}^\infty dy
 \left[V(x-y, t) f(y) + W(x-y,t)g(y)\right],$$
 where $f$ and $g$ are the initial data (in the notation of the
printed notes), and $W$ and $V$ are certain integral expressions.

 \item What identities for the Fourier transforms of delta
functions and step functions do you need to assume in order to get
your answer to agree with the one on p.\ 136 of the notes?
 Try to boil it down to simple formulas for functions (or
distributions) of {\sl one\/} variable, not three.
\end{enumerate}

 \item  Solve by the d'Alembert method
 (see pp.\ 136--139 of  notes)
  the wave equation for $0<x<\infty$
with Neumann boundary condition (${\partial 
u\over\partial x}(0,t)=0$) and
 initial data
 $$u(x,0) \equiv f(x) = e^{-100(x-10)^2}, \qquad
{\partial u\over \partial t}(x,0) \equiv g(x) =0.$$
 Sketch in space-time the pulses and the paths they follow.
 (The sketch should include at least the time interval
 $0\le t\le 15$.)

\item Same as the previous problem, but with Dirichlet boundary 
condition ($u(0,t)=0$) and initial data
 $$u(x,0) \equiv f(x) =0, \qquad 
{\partial u\over \partial t}(x,0) \equiv g(x)=
 x\,e^{-100(x-10)^2}.$$

                                                                                
\item Solve this problem in a quarter-disk 
($0<\theta<\frac{\pi}2$, $0\le r<1$):
$${\partial ^2u  \over \partial r^2} +\frac1r\,
{\partial u\over \partial r} + \frac1{r^2} {\partial ^2u\over 
\partial\theta^2} ={\partial u\over \partial t}\,,$$
$$u(t,r,0)=0=u(t,r,\pi/2), \qquad
{\partial u\over\partial r}(t,1,\theta) = 0,$$
$$u(0,r,\theta) = g(r,\theta).$$


\end{enumerate}
\end{document}
